There are some white and purple marbles in a box. If 2 white marbles are removed from the box, the total number of marbles left will be 7 times the number of white marbles left. If 6 purple marbles are removed from the box, the total number of marbles left will be 5 times the number of white marbles. How many marbles are there in the box?
|
Case 1 |
Case 2 |
|
White marbles |
Purple marbles |
White marbles |
Purple marbles |
Before |
1 u + 2 |
6 u |
1 p |
4 p + 6 |
Change |
- 2 |
|
|
- 6 |
After |
1 u |
6 u |
1 p |
4 p |
Number of purple marbles in the end for Case 1
= 7 u - 1 u
= 6 u
Number of white marbles in the end for Case 2
= 5 p - 1 p
= 4 p
The number of white marbles at first is the same for Case 1 and Case 2.
The number of purple marbles at first is also the same for Case 1 and Case 2.
1 u + 2 = 1 p --- (1)
6 u = 4 p + 6
6 u - 6 =
4 p --- (2)
Make p the same.
(1)
x4 4 u + 8 =
4 p --- (3)
(2) = (3)
6 u - 6 = 4 u + 8
6 u - 4 u = 8 + 6
2 u = 14
1 u = 14 ÷ 2 = 7
Number of marbles in the box
= (1 u + 2) + 6 u
= 7 u + 2
= (7 x 7) + 2
= 49 + 2
= 51
Answer(s): 51