There are some red and black marbles in a container. If 2 red marbles are removed from the container, the total number of marbles left will be 9 times the number of red marbles left. If 32 black marbles are removed from the container, the total number of marbles left will be 5 times the number of red marbles. How many marbles are there in the container?
|
Case 1 |
Case 2 |
|
Red marbles |
Black marbles |
Red marbles |
Black marbles |
Before |
1 u + 2 |
8 u |
1 p |
4 p + 32 |
Change |
- 2 |
|
|
- 32 |
After |
1 u |
8 u |
1 p |
4 p |
Number of black marbles in the end for Case 1
= 9 u - 1 u
= 8 u
Number of red marbles in the end for Case 2
= 5 p - 1 p
= 4 p
The number of red marbles at first is the same for Case 1 and Case 2.
The number of black marbles at first is also the same for Case 1 and Case 2.
1 u + 2 = 1 p --- (1)
8 u = 4 p + 32
8 u - 32 =
4 p --- (2)
Make p the same.
(1)
x4 4 u + 8 =
4 p --- (3)
(2) = (3)
8 u - 32 = 4 u + 8
8 u - 4 u = 8 + 32
4 u = 40
1 u = 40 ÷ 4 = 10
Number of marbles in the container
= (1 u + 2) + 8 u
= 9 u + 2
= (9 x 10) + 2
= 90 + 2
= 92
Answer(s): 92