There are some black and white marbles in a box. If 2 black marbles are removed from the box, the total number of marbles left will be 8 times the number of black marbles left. If 36 white marbles are removed from the box, the total number of marbles left will be 3 times the number of black marbles. How many marbles are there in the box?
|
Case 1 |
Case 2 |
|
Black marbles |
White marbles |
Black marbles |
White marbles |
Before |
1 u + 2 |
7 u |
1 p |
2 p + 36 |
Change |
- 2 |
|
|
- 36 |
After |
1 u |
7 u |
1 p |
2 p |
Number of white marbles in the end for Case 1
= 8 u - 1 u
= 7 u
Number of black marbles in the end for Case 2
= 3 p - 1 p
= 2 p
The number of black marbles at first is the same for Case 1 and Case 2.
The number of white marbles at first is also the same for Case 1 and Case 2.
1 u + 2 = 1 p --- (1)
7 u = 2 p + 36
7 u - 36 =
2 p --- (2)
Make p the same.
(1)
x2 2 u + 4 =
2 p --- (3)
(2) = (3)
7 u - 36 = 2 u + 4
7 u - 2 u = 4 + 36
5 u = 40
1 u = 40 ÷ 5 = 8
Number of marbles in the box
= (1 u + 2) + 7 u
= 8 u + 2
= (8 x 8) + 2
= 64 + 2
= 66
Answer(s): 66