There are some black and grey beads in a box. If 8 black beads are removed from the box, the total number of beads left will be 9 times the number of black beads left. If 11 grey beads are removed from the box, the total number of beads left will be 4 times the number of black beads. How many beads are there in the box?
|
Case 1 |
Case 2 |
|
Black beads |
Grey beads |
Black beads |
Grey beads |
Before |
1 u + 8 |
8 u |
1 p |
3 p + 11 |
Change |
- 8 |
|
|
- 11 |
After |
1 u |
8 u |
1 p |
3 p |
Number of grey beads in the end for Case 1
= 9 u - 1 u
= 8 u
Number of black beads in the end for Case 2
= 4 p - 1 p
= 3 p
The number of black beads at first is the same for Case 1 and Case 2.
The number of grey beads at first is also the same for Case 1 and Case 2.
1 u + 8 = 1 p --- (1)
8 u = 3 p + 11
8 u - 11 =
3 p --- (2)
Make p the same.
(1)
x3 3 u + 24 =
3 p --- (3)
(2) = (3)
8 u - 11 = 3 u + 24
8 u - 3 u = 24 + 11
5 u = 35
1 u = 35 ÷ 5 = 7
Number of beads in the box
= (1 u + 8) + 8 u
= 9 u + 8
= (9 x 7) + 8
= 63 + 8
= 71
Answer(s): 71