There are some silver and green marbles in a container. If 2 silver marbles are removed from the container, the total number of marbles left will be 7 times the number of silver marbles left. If 16 green marbles are removed from the container, the total number of marbles left will be 5 times the number of silver marbles. How many marbles are there in the container?
|
Case 1 |
Case 2 |
|
Silver marbles |
Green marbles |
Silver marbles |
Green marbles |
Before |
1 u + 2 |
6 u |
1 p |
4 p + 16 |
Change |
- 2 |
|
|
- 16 |
After |
1 u |
6 u |
1 p |
4 p |
Number of green marbles in the end for Case 1
= 7 u - 1 u
= 6 u
Number of silver marbles in the end for Case 2
= 5 p - 1 p
= 4 p
The number of silver marbles at first is the same for Case 1 and Case 2.
The number of green marbles at first is also the same for Case 1 and Case 2.
1 u + 2 = 1 p --- (1)
6 u = 4 p + 16
6 u - 16 =
4 p --- (2)
Make p the same.
(1)
x4 4 u + 8 =
4 p --- (3)
(2) = (3)
6 u - 16 = 4 u + 8
6 u - 4 u = 8 + 16
2 u = 24
1 u = 24 ÷ 2 = 12
Number of marbles in the container
= (1 u + 2) + 6 u
= 7 u + 2
= (7 x 12) + 2
= 84 + 2
= 86
Answer(s): 86