Jade has some chocolate bars and caramel apples. If she packs a chocolate bar and a caramel apple in each bag, there will be 26 caramel apples left. If she packs 3 chocolate bars and 4 caramel apples in each bag, there will be 16 chocolate bars left. How many chocolate bars and caramel apples does she have in all?
|
Case 1 |
Case 2 |
|
Chocolate Bars |
Caramel Apples |
Chocolate Bars |
Caramel Apples |
Before |
1 u |
1 u + 26 |
3 p + 16 |
4 p |
Change |
- 1 u |
- 1 u |
- 3 p |
- 4 p |
After |
0 |
26 |
16 |
0 |
The number of chocolate bars at first is the same for Case 1 and 2.
The number of caramel apples at first is also the same for Case 1 and 2.
1 u = 3 p + 16 --- (1)
1 u + 26 = 4 p
1 u = 4 p - 26 --- (2)
(2) = (1)
4 p - 26 = 3 p + 16
4 p - 3 p = 16 + 26
1 p = 42
Total number of chocolate bars and caramel apples
= (3 p + 16) + 4 p
= 7 p + 16
= 7 x 42 + 16
= 294 + 16
= 310
Answer(s): 310