Jack and Ahmad were given some allowances each. If Jack spent $21 each day and Ahmad spent $63 each day, Jack would still have $1234 left when Ahmad spent all his allowance. If Jack spent $63 each day and Ahmad spent $21 each day, Jack would still have $58 left when Ahmad spent all his allowance.
- How much allowance did Jack receive?
- How much allowance did Ahmad receive?
|
Case 1 |
Case 2 |
|
Jack |
Ahmad |
Jack |
Ahmad |
Before |
1 u + 1234 |
3 u |
3 p + 58 |
1 p |
Change |
- 1 u |
- 3 u |
- 3 p |
- 1 p |
After |
1234 |
0 |
58 |
0 |
(a)
Simplify the ratio.
21 : 63 = 1 : 3
The allowance that Ahmad had at first is the same for Case 1 and Case 2.
1 p = 3 u
3 p = 9 u
The allowance that Jack had at first is the same for Case 1 and Case 2.
9 u + 58 = 1 u + 1234
9 u - 1 u = 1234 - 58
8 u = 1176
1 u = 1176 ÷ 8 = 147
Allowance that Jack received
= 1 u + 1234
= 147 + 1234
= $1381
(b)
Allowance that Ahmad received
= 3 u
= 3 x 147
= $441
Answers: (a) $1381; (b) $441