Xavier and Cole were given some allowances each. If Xavier spent $14 each day and Cole spent $28 each day, Xavier would still have $750 left when Cole spent all his allowance. If Xavier spent $28 each day and Cole spent $14 each day, Xavier would still have $36 left when Cole spent all his allowance.
- How much allowance did Xavier receive?
- How much allowance did Cole receive?
|
Case 1 |
Case 2 |
|
Xavier |
Cole |
Xavier |
Cole |
Before |
1 u + 750 |
2 u |
2 p + 36 |
1 p |
Change |
- 1 u |
- 2 u |
- 2 p |
- 1 p |
After |
750 |
0 |
36 |
0 |
(a)
Simplify the ratio.
14 : 28 = 1 : 2
The allowance that Cole had at first is the same for Case 1 and Case 2.
1 p = 2 u
2 p = 4 u
The allowance that Xavier had at first is the same for Case 1 and Case 2.
4 u + 36 = 1 u + 750
4 u - 1 u = 750 - 36
3 u = 714
1 u = 714 ÷ 3 = 238
Allowance that Xavier received
= 1 u + 750
= 238 + 750
= $988
(b)
Allowance that Cole received
= 2 u
= 2 x 238
= $476
Answers: (a) $988; (b) $476