Sean and Xavier were given some allowances each. If Sean spent $16 each day and Xavier spent $48 each day, Sean would still have $1444 left when Xavier spent all his allowance. If Sean spent $48 each day and Xavier spent $16 each day, Sean would still have $36 left when Xavier spent all his allowance.
- How much allowance did Sean receive?
- How much allowance did Xavier receive?
|
Case 1 |
Case 2 |
|
Sean |
Xavier |
Sean |
Xavier |
Before |
1 u + 1444 |
3 u |
3 p + 36 |
1 p |
Change |
- 1 u |
- 3 u |
- 3 p |
- 1 p |
After |
1444 |
0 |
36 |
0 |
(a)
Simplify the ratio.
16 : 48 = 1 : 3
The allowance that Xavier had at first is the same for Case 1 and Case 2.
1 p = 3 u
3 p = 9 u
The allowance that Sean had at first is the same for Case 1 and Case 2.
9 u + 36 = 1 u + 1444
9 u - 1 u = 1444 - 36
8 u = 1408
1 u = 1408 ÷ 8 = 176
Allowance that Sean received
= 1 u + 1444
= 176 + 1444
= $1620
(b)
Allowance that Xavier received
= 3 u
= 3 x 176
= $528
Answers: (a) $1620; (b) $528