Pierre and Bryan were given some allowances each. If Pierre spent $16 each day and Bryan spent $48 each day, Pierre would still have $2730 left when Bryan spent all his allowance. If Pierre spent $48 each day and Bryan spent $16 each day, Pierre would still have $42 left when Bryan spent all his allowance.
- How much allowance did Pierre receive?
- How much allowance did Bryan receive?
|
Case 1 |
Case 2 |
|
Pierre |
Bryan |
Pierre |
Bryan |
Before |
1 u + 2730 |
3 u |
3 p + 42 |
1 p |
Change |
- 1 u |
- 3 u |
- 3 p |
- 1 p |
After |
2730 |
0 |
42 |
0 |
(a)
Simplify the ratio.
16 : 48 = 1 : 3
The allowance that Bryan had at first is the same for Case 1 and Case 2.
1 p = 3 u
3 p = 9 u
The allowance that Pierre had at first is the same for Case 1 and Case 2.
9 u + 42 = 1 u + 2730
9 u - 1 u = 2730 - 42
8 u = 2688
1 u = 2688 ÷ 8 = 336
Allowance that Pierre received
= 1 u + 2730
= 336 + 2730
= $3066
(b)
Allowance that Bryan received
= 3 u
= 3 x 336
= $1008
Answers: (a) $3066; (b) $1008