Pierre and Riordan were given some allowances each. If Pierre spent $19 each day and Riordan spent $38 each day, Pierre would still have $707 left when Riordan spent all his allowance. If Pierre spent $38 each day and Riordan spent $19 each day, Pierre would still have $23 left when Riordan spent all his allowance.
- How much allowance did Pierre receive?
- How much allowance did Riordan receive?
|
Case 1 |
Case 2 |
|
Pierre |
Riordan |
Pierre |
Riordan |
Before |
1 u + 707 |
2 u |
2 p + 23 |
1 p |
Change |
- 1 u |
- 2 u |
- 2 p |
- 1 p |
After |
707 |
0 |
23 |
0 |
(a)
Simplify the ratio.
19 : 38 = 1 : 2
The allowance that Riordan had at first is the same for Case 1 and Case 2.
1 p = 2 u
2 p = 4 u
The allowance that Pierre had at first is the same for Case 1 and Case 2.
4 u + 23 = 1 u + 707
4 u - 1 u = 707 - 23
3 u = 684
1 u = 684 ÷ 3 = 228
Allowance that Pierre received
= 1 u + 707
= 228 + 707
= $935
(b)
Allowance that Riordan received
= 2 u
= 2 x 228
= $456
Answers: (a) $935; (b) $456