Xavier and Ahmad were given some allowances each. If Xavier spent $14 each day and Ahmad spent $42 each day, Xavier would still have $989 left when Ahmad spent all his allowance. If Xavier spent $42 each day and Ahmad spent $14 each day, Xavier would still have $93 left when Ahmad spent all his allowance.
- How much allowance did Xavier receive?
- How much allowance did Ahmad receive?
|
Case 1 |
Case 2 |
|
Xavier |
Ahmad |
Xavier |
Ahmad |
Before |
1 u + 989 |
3 u |
3 p + 93 |
1 p |
Change |
- 1 u |
- 3 u |
- 3 p |
- 1 p |
After |
989 |
0 |
93 |
0 |
(a)
Simplify the ratio.
14 : 42 = 1 : 3
The allowance that Ahmad had at first is the same for Case 1 and Case 2.
1 p = 3 u
3 p = 9 u
The allowance that Xavier had at first is the same for Case 1 and Case 2.
9 u + 93 = 1 u + 989
9 u - 1 u = 989 - 93
8 u = 896
1 u = 896 ÷ 8 = 112
Allowance that Xavier received
= 1 u + 989
= 112 + 989
= $1101
(b)
Allowance that Ahmad received
= 3 u
= 3 x 112
= $336
Answers: (a) $1101; (b) $336