Luke and Pierre were given some allowances each. If Luke spent $24 each day and Pierre spent $72 each day, Luke would still have $2346 left when Pierre spent all his allowance. If Luke spent $72 each day and Pierre spent $24 each day, Luke would still have $42 left when Pierre spent all his allowance.
- How much allowance did Luke receive?
- How much allowance did Pierre receive?
|
Case 1 |
Case 2 |
|
Luke |
Pierre |
Luke |
Pierre |
Before |
1 u + 2346 |
3 u |
3 p + 42 |
1 p |
Change |
- 1 u |
- 3 u |
- 3 p |
- 1 p |
After |
2346 |
0 |
42 |
0 |
(a)
Simplify the ratio.
24 : 72 = 1 : 3
The allowance that Pierre had at first is the same for Case 1 and Case 2.
1 p = 3 u
3 p = 9 u
The allowance that Luke had at first is the same for Case 1 and Case 2.
9 u + 42 = 1 u + 2346
9 u - 1 u = 2346 - 42
8 u = 2304
1 u = 2304 ÷ 8 = 288
Allowance that Luke received
= 1 u + 2346
= 288 + 2346
= $2634
(b)
Allowance that Pierre received
= 3 u
= 3 x 288
= $864
Answers: (a) $2634; (b) $864