Lee and Xavier were given some allowances each. If Lee spent $18 each day and Xavier spent $36 each day, Lee would still have $635 left when Xavier spent all his allowance. If Lee spent $36 each day and Xavier spent $18 each day, Lee would still have $95 left when Xavier spent all his allowance.
- How much allowance did Lee receive?
- How much allowance did Xavier receive?
|
Case 1 |
Case 2 |
|
Lee |
Xavier |
Lee |
Xavier |
Before |
1 u + 635 |
2 u |
2 p + 95 |
1 p |
Change |
- 1 u |
- 2 u |
- 2 p |
- 1 p |
After |
635 |
0 |
95 |
0 |
(a)
Simplify the ratio.
18 : 36 = 1 : 2
The allowance that Xavier had at first is the same for Case 1 and Case 2.
1 p = 2 u
2 p = 4 u
The allowance that Lee had at first is the same for Case 1 and Case 2.
4 u + 95 = 1 u + 635
4 u - 1 u = 635 - 95
3 u = 540
1 u = 540 ÷ 3 = 180
Allowance that Lee received
= 1 u + 635
= 180 + 635
= $815
(b)
Allowance that Xavier received
= 2 u
= 2 x 180
= $360
Answers: (a) $815; (b) $360