In a container, there are some pears and persimmons. If 90 more persimmons are put into the container, the percentage of pears will decrease from 70% to 25%. How many pears are there in the container?
|
Pears |
Persimmons |
Before |
7x1 = 7 u |
3x1 = 3 u |
Change |
No change |
+ 90 |
After |
1x7 = 7 u |
3x7 = 21 u |
70% =
70100 =
710 25% =
25100 =
14 The number of pears remains unchanged at first and in the end. Make the number of pears the same. LCM of 7 and 1 is 7.
Number of persimmons added
= 21 u - 3 u
= 18 u
18 u = 90
1 u = 90 ÷ 18 = 5
Number of pears
= 7 u
= 7 x 5
= 35
Answer(s): 35