In a container, there are some persimmons and mangoes. If 50 mangoes are removed from the container, the percentage of mangoes will increase from 20% to 60%. How many mangoes are there in the container?
| |
Persimmons |
Mangoes |
| Before |
1x3 =
3 u |
4x3 =
12 u |
| Change |
No change |
- 50 |
| After |
3x1 =
3 u |
2x1 =
2 u |
20% =
20100 =
15 60% =
60100 =
35 The number of persimmons remains unchanged at first and in the end. Make the number of persimmons the same. LCM of 3 and 1 is 3.
Number of mangoes removed
= 12 u - 2 u
= 10 u
10 u = 50
1 u = 50 ÷ 10 = 5
Number of mangoes
= 12 u
= 12 x 5
= 60
Answer(s): 60
