In a box, there are some chikoos and oranges. If 80 oranges are removed from the box, the percentage of oranges will increase from 30% to 70%. How many oranges are there in the box?
|
Chikoos |
Oranges |
Before |
3x7 = 21 u |
7x7 = 49 u |
Change |
No change |
- 80 |
After |
7x3 = 21 u |
3x3 = 9 u |
30% =
30100 =
310 70% =
70100 =
710 The number of chikoos remains unchanged at first and in the end. Make the number of chikoos the same. LCM of 7 and 3 is 21.
Number of oranges removed
= 49 u - 9 u
= 40 u
40 u = 80
1 u = 80 ÷ 40 = 2
Number of oranges
= 49 u
= 49 x 2
= 98
Answer(s): 98