In a container, there are some oranges and chikoos. If 75 chikoos are removed from the container, the percentage of chikoos will increase from 20% to 80%. How many chikoos are there in the container?
| |
Oranges |
Chikoos |
| Before |
1x4 =
4 u |
4x4 =
16 u |
| Change |
No change |
- 75 |
| After |
4x1 =
4 u |
1x1 =
1 u |
20% =
20100 =
15 80% =
80100 =
45 The number of oranges remains unchanged at first and in the end. Make the number of oranges the same. LCM of 4 and 1 is 4.
Number of chikoos removed
= 16 u - 1 u
= 15 u
15 u = 75
1 u = 75 ÷ 15 = 5
Number of chikoos
= 16 u
= 16 x 5
= 80
Answer(s): 80
