In a container, there are some pears and chikoos. If 30 chikoos are removed from the container, the percentage of chikoos will increase from 20% to 60%. How many chikoos are there in the container?
|
Pears |
Chikoos |
Before |
1x3 = 3 u |
4x3 = 12 u |
Change |
No change |
- 30 |
After |
3x1 = 3 u |
2x1 = 2 u |
20% =
20100 =
15 60% =
60100 =
35 The number of pears remains unchanged at first and in the end. Make the number of pears the same. LCM of 3 and 1 is 3.
Number of chikoos removed
= 12 u - 2 u
= 10 u
10 u = 30
1 u = 30 ÷ 10 = 3
Number of chikoos
= 12 u
= 12 x 3
= 36
Answer(s): 36