In a box, there are some persimmons and oranges. If 60 oranges are removed from the box, the percentage of oranges will increase from 20% to 80%. How many oranges are there in the box?
|
Persimmons |
Oranges |
Before |
1x4 = 4 u |
4x4 = 16 u |
Change |
No change |
- 60 |
After |
4x1 = 4 u |
1x1 = 1 u |
20% =
20100 =
15 80% =
80100 =
45 The number of persimmons remains unchanged at first and in the end. Make the number of persimmons the same. LCM of 4 and 1 is 4.
Number of oranges removed
= 16 u - 1 u
= 15 u
15 u = 60
1 u = 60 ÷ 15 = 4
Number of oranges
= 16 u
= 16 x 4
= 64
Answer(s): 64