In a box, there are some starfruits and oranges. If 42 oranges are removed from the box, the percentage of oranges will increase from 25% to 60%. How many oranges are there in the box?
|
Starfruits |
Oranges |
Before |
1x3 = 3 u |
3x3 = 9 u |
Change |
No change |
- 42 |
After |
3x1 = 3 u |
2x1 = 2 u |
25% =
25100 =
14 60% =
60100 =
35 The number of starfruits remains unchanged at first and in the end. Make the number of starfruits the same. LCM of 3 and 1 is 3.
Number of oranges removed
= 9 u - 2 u
= 7 u
7 u = 42
1 u = 42 ÷ 7 = 6
Number of oranges
= 9 u
= 9 x 6
= 54
Answer(s): 54