In a container, there are some pears and starfruits. If 33 starfruits are removed from the container, the percentage of starfruits will increase from 25% to 80%. How many starfruits are there in the container?
|
Pears |
Starfruits |
Before |
1x4 = 4 u |
3x4 = 12 u |
Change |
No change |
- 33 |
After |
4x1 = 4 u |
1x1 = 1 u |
25% =
25100 =
14 80% =
80100 =
45 The number of pears remains unchanged at first and in the end. Make the number of pears the same. LCM of 4 and 1 is 4.
Number of starfruits removed
= 12 u - 1 u
= 11 u
11 u = 33
1 u = 33 ÷ 11 = 3
Number of starfruits
= 12 u
= 12 x 3
= 36
Answer(s): 36