Abi and Hazel collected beads. Hazel gave 70% of her beads to Abi. As a result, Abi's beads increased by 20%. If Abi had 168 beads left, find the total number of beads the two girls had at first.
| |
Comparing the change
in Hazel's beads |
Hazel |
Abi |
| Before |
10x1 =
10 u |
|
5x7 =
35 u |
| Change |
- 7x1 =
- 7 u |
- 1x7 =
- 7 u |
+ 1x7 =
+ 7 u |
| After |
3x1 =
3 u |
|
6x7 =
42 u |
70% =
70100 =
710 20% =
20100 =
15 The number of beads that Abi gave to Hazel is repeated. Make the number of beads that Abi gave to Hazel the same. LCM of 1 and 7 is 7.
Number of beads that Abi had in the end = 42 u
42 u = 168
1 u = 168 ÷ 42 = 4
Number of beads that Hazel and Abi had at first
= 10 u + 35 u
= 45 u
= 45 x 4
= 180
Answer(s): 180
