Diana and Fanny collected buttons. Diana gave 40% of her buttons to Fanny. As a result, Fanny's buttons increased by 80%. If Diana had 54 buttons left, find the total number of buttons the two girls had at first.
|
Diana |
Fanny |
Comparing the change in Fanny's buttons |
Before |
5x2 = 10 u |
|
5x1 = 5 u |
Change |
- 2x2 = - 4 u |
+ 2x2 = + 4 u |
+ 4x1 = + 4 u |
After |
3x2 = 6 u |
|
9x1 = 9 u |
40% =
40100 =
25 80% =
80100 =
45 The number of buttons that Diana gave to Fanny is repeated. Make the number of buttons that Diana gave to Fanny the same. LCM of 2 and 4 is 4.
Number of buttons that Diana had in the end = 6 u
6 u = 54
1 u = 54 ÷ 6 = 9
Number of buttons that Diana and Fanny had at first
= 10 u + 5 u
= 15 u
= 15 x 9
= 135
Answer(s): 135