Hilda and Min collected coins. Min gave 75% of her coins to Hilda. As a result, Hilda's coins increased by 40%. If Hilda had 147 coins left, find the total number of coins the two girls had at first.
| |
Comparing the change
in Min's coins |
Min |
Hilda |
| Before |
4x2 =
8 u |
|
5x3 =
15 u |
| Change |
- 3x2 =
- 6 u |
- 2x3 =
- 6 u |
+ 2x3 =
+ 6 u |
| After |
1x2 =
2 u |
|
7x3 =
21 u |
75% =
75100 =
34 40% =
40100 =
25 The number of coins that Hilda gave to Min is repeated. Make the number of coins that Hilda gave to Min the same. LCM of 2 and 3 is 6.
Number of coins that Hilda had in the end = 21 u
21 u = 147
1 u = 147 ÷ 21 = 7
Number of coins that Min and Hilda had at first
= 8 u + 15 u
= 23 u
= 23 x 7
= 161
Answer(s): 161
