Marion and Raeann collected cards. Raeann gave 80% of her cards to Marion. As a result, Marion's cards increased by 10%. If Marion had 528 cards left, find the total number of cards the two girls had at first.
|
Comparing the change in Raeann's cards |
Raeann |
Marion |
Before |
5x1 = 5 u |
|
10x4 = 40 u |
Change |
- 4x1 = - 4 u |
- 1x4 = - 4 u |
+ 1x4 = + 4 u |
After |
1x1 = 1 u |
|
11x4 = 44 u |
80% =
80100 =
45 10% =
10100 =
110 The number of cards that Marion gave to Raeann is repeated. Make the number of cards that Marion gave to Raeann the same. LCM of 1 and 4 is 4.
Number of cards that Marion had in the end = 44 u
44 u = 528
1 u = 528 ÷ 44 = 12
Number of cards that Raeann and Marion had at first
= 5 u + 40 u
= 45 u
= 45 x 12
= 540
Answer(s): 540