Kimberly and Winnie collected coins. Kimberly gave 30% of her coins to Winnie. As a result, Winnie's coins increased by 80%. If Kimberly had 196 coins left, find the total number of coins the two girls had at first.
| |
Kimberly |
Winnie |
Comparing the change
in Winnie's coins |
| Before |
10x4 =
40 u |
|
5x3 =
15 u |
| Change |
- 3x4 =
- 12 u |
+ 3x4 =
+ 12 u |
+ 4x3 =
+ 12 u |
| After |
7x4 =
28 u |
|
9x3 =
27 u |
30% =
30100 =
310 80% =
80100 =
45 The number of coins that Kimberly gave to Winnie is repeated. Make the number of coins that Kimberly gave to Winnie the same. LCM of 3 and 4 is 12.
Number of coins that Kimberly had in the end = 28 u
28 u = 196
1 u = 196 ÷ 28 = 7
Number of coins that Kimberly and Winnie had at first
= 40 u + 15 u
= 55 u
= 55 x 7
= 385
Answer(s): 385
