Kimberly and Roshel collected stickers. Roshel gave 75% of her stickers to Kimberly. As a result, Kimberly's stickers increased by 40%. If Kimberly had 105 stickers left, find the total number of stickers the two girls had at first.
| |
Comparing the change
in Roshel's stickers |
Roshel |
Kimberly |
| Before |
4x2 =
8 u |
|
5x3 =
15 u |
| Change |
- 3x2 =
- 6 u |
- 2x3 =
- 6 u |
+ 2x3 =
+ 6 u |
| After |
1x2 =
2 u |
|
7x3 =
21 u |
75% =
75100 =
34 40% =
40100 =
25 The number of stickers that Kimberly gave to Roshel is repeated. Make the number of stickers that Kimberly gave to Roshel the same. LCM of 2 and 3 is 6.
Number of stickers that Kimberly had in the end = 21 u
21 u = 105
1 u = 105 ÷ 21 = 5
Number of stickers that Roshel and Kimberly had at first
= 8 u + 15 u
= 23 u
= 23 x 5
= 115
Answer(s): 115
