Elyse and Pamela collected beads. Elyse gave 40% of her beads to Pamela. As a result, Pamela's beads increased by 80%. If Elyse had 54 beads left, find the total number of beads the two girls had at first.
| |
Elyse |
Pamela |
Comparing the change
in Pamela's beads |
| Before |
5x2 =
10 u |
|
5x1 =
5 u |
| Change |
- 2x2 =
- 4 u |
+ 2x2 =
+ 4 u |
+ 4x1 =
+ 4 u |
| After |
3x2 =
6 u |
|
9x1 =
9 u |
40% =
40100 =
25 80% =
80100 =
45 The number of beads that Elyse gave to Pamela is repeated. Make the number of beads that Elyse gave to Pamela the same. LCM of 2 and 4 is 4.
Number of beads that Elyse had in the end = 6 u
6 u = 54
1 u = 54 ÷ 6 = 9
Number of beads that Elyse and Pamela had at first
= 10 u + 5 u
= 15 u
= 15 x 9
= 135
Answer(s): 135
