Yoko and Penelope collected beads. Penelope gave 60% of her beads to Yoko. As a result, Yoko's beads increased by 20%. If Yoko had 108 beads left, find the total number of beads the two girls had at first.
| |
Comparing the change
in Penelope's beads |
Penelope |
Yoko |
| Before |
5x1 =
5 u |
|
5x3 =
15 u |
| Change |
- 3x1 =
- 3 u |
- 1x3 =
- 3 u |
+ 1x3 =
+ 3 u |
| After |
2x1 =
2 u |
|
6x3 =
18 u |
60% =
60100 =
35 20% =
20100 =
15 The number of beads that Yoko gave to Penelope is repeated. Make the number of beads that Yoko gave to Penelope the same. LCM of 1 and 3 is 3.
Number of beads that Yoko had in the end = 18 u
18 u = 108
1 u = 108 ÷ 18 = 6
Number of beads that Penelope and Yoko had at first
= 5 u + 15 u
= 20 u
= 20 x 6
= 120
Answer(s): 120
