Hilda and Xylia collected marbles. Hilda gave 20% of her marbles to Xylia. As a result, Xylia's marbles increased by 60%. If Hilda had 96 marbles left, find the total number of marbles the two girls had at first.
|
Hilda |
Xylia |
Comparing the change in Xylia's marbles |
Before |
5x3 = 15 u |
|
5x1 = 5 u |
Change |
- 1x3 = - 3 u |
+ 1x3 = + 3 u |
+ 3x1 = + 3 u |
After |
4x3 = 12 u |
|
8x1 = 8 u |
20% =
20100 =
15 60% =
60100 =
35 The number of marbles that Hilda gave to Xylia is repeated. Make the number of marbles that Hilda gave to Xylia the same. LCM of 1 and 3 is 3.
Number of marbles that Hilda had in the end = 12 u
12 u = 96
1 u = 96 ÷ 12 = 8
Number of marbles that Hilda and Xylia had at first
= 15 u + 5 u
= 20 u
= 20 x 8
= 160
Answer(s): 160