Albert was fixing a jigsaw puzzle. By the third day, the number of pieces he fixed was 30% of the number of pieces unfixed. After another 4 days, he fixed another 592 pieces and the number of unfixed pieces he was left with was 25% of the number of pieces fixed. How many pieces were left unfixed?
|
Fixed |
Unfixed |
Total |
Before |
3x5 = 15 u |
10x5 = 50 u |
13x5 = 65 u |
Change |
+ 592 |
- 592 |
|
After |
4x13 = 52 u |
1x13 = 13 u |
5x13 = 65 u |
30% =
30100 =
310 25% =
30100 =
14 Since this is a jigsaw puzzle, there is no change in the total number of jigsaw pieces. Make the total number of jigsaw pieces the same. LCM of 13 and 5 is 65.
Number of additional pieces of jigsaw puzzle that Albert fixed
= 52 u - 15 u
= 37 u
37 u = 592
1 u = 592 ÷ 37 = 16
Number of pieces that were left unfixed
= 13 u
= 13 x 16
= 208
Answer(s): 208