Carl was fixing a jigsaw puzzle. By the fourth day, the number of pieces he fixed was 25% of the number of pieces unfixed. After another 8 days, he fixed another 117 pieces and the number of unfixed pieces he was left with was 10% of the number of pieces fixed. How many pieces were left unfixed?
| |
Fixed |
Unfixed |
Total |
| Before |
1x11 =
11 u |
4x11 =
44 u |
5x11 =
55 u |
| Change |
+ 117 |
- 117 |
|
| After |
10x5 =
50 u |
1x5 =
5 u |
11x5 =
55 u |
25% =
25100 =
14 10% =
25100 =
110 Since this is a jigsaw puzzle, there is no change in the total number of jigsaw pieces. Make the total number of jigsaw pieces the same. LCM of 5 and 11 is 55.
Number of additional pieces of jigsaw puzzle that Carl fixed
= 50 u - 11 u
= 39 u
39 u = 117
1 u = 117 ÷ 39 = 3
Number of pieces that were left unfixed
= 5 u
= 5 x 3
= 15
Answer(s): 15
