Pierre was fixing a jigsaw puzzle. By the fourth day, the number of pieces he fixed was 10% of the number of pieces unfixed. After another 7 days, he fixed another 585 pieces and the number of unfixed pieces he was left with was 25% of the number of pieces fixed. How many pieces were left unfixed?
| |
Fixed |
Unfixed |
Total |
| Before |
1x5 =
5 u |
10x5 =
50 u |
11x5 =
55 u |
| Change |
+ 585 |
- 585 |
|
| After |
4x11 =
44 u |
1x11 =
11 u |
5x11 =
55 u |
10% =
10100 =
110 25% =
10100 =
14 Since this is a jigsaw puzzle, there is no change in the total number of jigsaw pieces. Make the total number of jigsaw pieces the same. LCM of 11 and 5 is 55.
Number of additional pieces of jigsaw puzzle that Pierre fixed
= 44 u - 5 u
= 39 u
39 u = 585
1 u = 585 ÷ 39 = 15
Number of pieces that were left unfixed
= 11 u
= 11 x 15
= 165
Answer(s): 165
