Sean had 60 more stickers than Brandon. Sean gave 25% of his stickers to Brandon. Brandon in return gave 60% of his stickers to Sean. In the end, Brandon had 208 less stickers than Sean. How many stickers did Sean have at first?
| |
Sean |
Brandon |
Comparing Sean
and Peter at first |
60 more |
|
| Before |
4 u + 60 |
4 u |
| Change 1 |
- 1 u - 15 |
+ 1 u + 15 |
| After 1 |
3 u + 45 |
5 u + 15 |
| Change 2 |
+ 3 u + 9 |
- 3 u - 9 |
| After 2 |
6 u + 54 |
2 u + 6 |
25% =
25100 =
1425% x 60
=
25100 x 60
= 15
60% x 15
=
60100 x 15
= 9
60% x 5 u
=
60100 x 5 u
= 3 u
Brandon had 208 less stickers than Sean in the end. If another 208 stickers are given to Brandon, both will have the same number of stickers.
6 u + 54 = 2 u + 6 + 208
6 u - 2 u = 6 + 208 - 54
4 u = 160
1 u = 160 ÷ 4 = 40
Number of Brandon's stickers at first
= 4 u
= 4 x 40
= 160
Answer: 160
