Xavier had 120 more coins than Brandon. Xavier gave 25% of his coins to Brandon. Brandon in return gave 80% of his coins to Xavier. In the end, Brandon had 278 less coins than Xavier. How many coins did Xavier have at first?
| |
Xavier |
Brandon |
Comparing Xavier
and Peter at first |
120 more |
|
| Before |
4 u + 120 |
4 u |
| Change 1 |
- 1 u - 30 |
+ 1 u + 30 |
| After 1 |
3 u + 90 |
5 u + 30 |
| Change 2 |
+ 4 u + 24 |
- 4 u - 24 |
| After 2 |
7 u + 114 |
1 u + 6 |
25% =
25100 =
1425% x 120
=
25100 x 120
= 30
80% x 30
=
80100 x 30
= 24
80% x 5 u
=
80100 x 5 u
= 4 u
Brandon had 278 less coins than Xavier in the end. If another 278 coins are given to Brandon, both will have the same number of coins.
7 u + 114 = 1 u + 6 + 278
7 u - 1 u = 6 + 278 - 114
6 u = 170
1 u = 170 ÷ 6 = 34
Number of Brandon's coins at first
= 4 u
= 4 x 34
= 136
Answer: 136
