Ivan had 80 more coins than George. Ivan gave 25% of his coins to George. George in return gave 60% of his coins to Ivan. In the end, Ivan had 274 more coins than George. How many coins did Ivan have at first?
| |
Ivan |
George |
Comparing Ivan
and Peter at first |
80 more |
|
| Before |
4 u + 80 |
4 u |
| Change 1 |
- 1 u - 20 |
+ 1 u + 20 |
| After 1 |
3 u + 60 |
5 u + 20 |
| Change 2 |
+ 3 u + 12 |
- 3 u - 12 |
| After 2 |
6 u + 72 |
2 u + 8 |
25% =
25100 =
1425% x 80
=
25100 x 80
= 20
60% x 20
=
60100 x 20
= 12
60% x 5 u
=
60100 x 5 u
= 3 u
Ivan had 274 more coins than George in the end. If another 274 coins are given to George, both will have the same number of coins.
6 u + 72 = 2 u + 8 + 274
6 u - 2 u = 8 + 274 - 72
6 u = 210
1 u = 210 ÷ 6 = 35
Number of Ivan's coins at first
= 4 u + 80
= 4 x 35 + 80
= 140 + 80
= 220
Answer: 220
