Luis had 60 more beads than Tommy. Luis gave 25% of his beads to Tommy. Tommy in return gave 80% of his beads to Luis. In the end, Tommy had 110 less beads than Luis. How many beads did Luis have at first?
| |
Luis |
Tommy |
Comparing Luis
and Peter at first |
60 more |
|
| Before |
4 u + 60 |
4 u |
| Change 1 |
- 1 u - 15 |
+ 1 u + 15 |
| After 1 |
3 u + 45 |
5 u + 15 |
| Change 2 |
+ 4 u + 12 |
- 4 u - 12 |
| After 2 |
7 u + 57 |
1 u + 3 |
25% =
25100 =
1425% x 60
=
25100 x 60
= 15
80% x 15
=
80100 x 15
= 12
80% x 5 u
=
80100 x 5 u
= 4 u
Tommy had 110 less beads than Luis in the end. If another 110 beads are given to Tommy, both will have the same number of beads.
7 u + 57 = 1 u + 3 + 110
7 u - 1 u = 3 + 110 - 57
6 u = 56
1 u = 56 ÷ 6 = 28
Number of Tommy's beads at first
= 4 u
= 4 x 28
= 112
Answer: 112
