Ben had 160 more coins than Henry. Ben gave 25% of his coins to Henry. Henry in return gave 80% of his coins to Ben. In the end, Henry had 291 less coins than Ben. How many coins did Ben have at first?
| |
Ben |
Henry |
Comparing Ben
and Peter at first |
160 more |
|
| Before |
4 u + 160 |
4 u |
| Change 1 |
- 1 u - 40 |
+ 1 u + 40 |
| After 1 |
3 u + 120 |
5 u + 40 |
| Change 2 |
+ 4 u + 32 |
- 4 u - 32 |
| After 2 |
7 u + 152 |
1 u + 8 |
25% =
25100 =
1425% x 160
=
25100 x 160
= 40
80% x 40
=
80100 x 40
= 32
80% x 5 u
=
80100 x 5 u
= 4 u
Henry had 291 less coins than Ben in the end. If another 291 coins are given to Henry, both will have the same number of coins.
7 u + 152 = 1 u + 8 + 291
7 u - 1 u = 8 + 291 - 152
6 u = 147
1 u = 147 ÷ 6 = 21
Number of Henry's coins at first
= 4 u
= 4 x 21
= 84
Answer: 84
