Liam had 190 more erasers than Jenson. Liam gave 20% of his erasers to Jenson. Jenson in return gave 50% of his erasers to Liam. In the end, Jenson had 648 less erasers than Liam. How many erasers did Liam have at first?
|
Liam |
Jenson |
Comparing Liam and Peter at first |
190 more |
|
Before |
5 u + 190 |
5 u |
Change 1 |
- 1 u - 38 |
+ 1 u + 38 |
After 1 |
4 u + 152 |
6 u + 38 |
Change 2 |
+ 3 u + 19 |
- 3 u - 19 |
After 2 |
7 u + 171 |
3 u + 19 |
20% =
20100 =
1520% x 190
=
20100 x 190
= 38
50% x 38
=
50100 x 38
= 19
50% x 6 u
=
50100 x 6 u
= 3 u
Jenson had 648 less erasers than Liam in the end. If another 648 erasers are given to Jenson, both will have the same number of erasers.
7 u + 171 = 3 u + 19 + 648
7 u - 3 u = 19 + 648 - 171
4 u = 496
1 u = 496 ÷ 4 = 31
Number of Jenson's erasers at first
= 5 u
= 5 x 31
= 155
Answer: 155