Vincent had 60 more coins than Sean. Vincent gave 20% of his coins to Sean. Sean in return gave 50% of his coins to Vincent. In the end, Vincent had 111 more coins than Sean. How many coins did Vincent have at first?
| |
Vincent |
Sean |
Comparing Vincent
and Peter at first |
60 more |
|
| Before |
5 u + 60 |
5 u |
| Change 1 |
- 1 u - 12 |
+ 1 u + 12 |
| After 1 |
4 u + 48 |
6 u + 12 |
| Change 2 |
+ 3 u + 6 |
- 3 u - 6 |
| After 2 |
7 u + 54 |
3 u + 6 |
20% =
20100 =
1520% x 60
=
20100 x 60
= 12
50% x 12
=
50100 x 12
= 6
50% x 6 u
=
50100 x 6 u
= 3 u
Vincent had 111 more coins than Sean in the end. If another 111 coins are given to Sean, both will have the same number of coins.
7 u + 54 = 3 u + 6 + 111
7 u - 3 u = 6 + 111 - 54
3 u = 63
1 u = 63 ÷ 3 = 21
Number of Vincent's coins at first
= 5 u + 60
= 5 x 21 + 60
= 105 + 60
= 165
Answer: 165
