Pierre had 80 more stickers than Archie. Pierre gave 25% of his stickers to Archie. Archie in return gave 80% of his stickers to Pierre. In the end, Archie had 180 less stickers than Pierre. How many stickers did Pierre have at first?
|
Pierre |
Archie |
Comparing Pierre and Peter at first |
80 more |
|
Before |
4 u + 80 |
4 u |
Change 1 |
- 1 u - 20 |
+ 1 u + 20 |
After 1 |
3 u + 60 |
5 u + 20 |
Change 2 |
+ 4 u + 16 |
- 4 u - 16 |
After 2 |
7 u + 76 |
1 u + 4 |
25% =
25100 =
1425% x 80
=
25100 x 80
= 20
80% x 20
=
80100 x 20
= 16
80% x 5 u
=
80100 x 5 u
= 4 u
Archie had 180 less stickers than Pierre in the end. If another 180 stickers are given to Archie, both will have the same number of stickers.
7 u + 76 = 1 u + 4 + 180
7 u - 1 u = 4 + 180 - 76
6 u = 108
1 u = 108 ÷ 6 = 36
Number of Archie's stickers at first
= 4 u
= 4 x 36
= 144
Answer: 144