Seth had 50 more stickers than Ian. Seth gave 20% of his stickers to Ian. Ian in return gave 50% of his stickers to Seth. In the end, Ian had 92 less stickers than Seth. How many stickers did Seth have at first?
| |
Seth |
Ian |
Comparing Seth
and Peter at first |
50 more |
|
| Before |
5 u + 50 |
5 u |
| Change 1 |
- 1 u - 10 |
+ 1 u + 10 |
| After 1 |
4 u + 40 |
6 u + 10 |
| Change 2 |
+ 3 u + 5 |
- 3 u - 5 |
| After 2 |
7 u + 45 |
3 u + 5 |
20% =
20100 =
1520% x 50
=
20100 x 50
= 10
50% x 10
=
50100 x 10
= 5
50% x 6 u
=
50100 x 6 u
= 3 u
Ian had 92 less stickers than Seth in the end. If another 92 stickers are given to Ian, both will have the same number of stickers.
7 u + 45 = 3 u + 5 + 92
7 u - 3 u = 5 + 92 - 45
4 u = 52
1 u = 52 ÷ 4 = 26
Number of Ian's stickers at first
= 5 u
= 5 x 26
= 130
Answer: 130
