Ivan had 130 more cards than Lee. Ivan gave 20% of his cards to Lee. Lee in return gave 50% of his cards to Ivan. In the end, Lee had 334 less cards than Ivan. How many cards did Ivan have at first?
| |
Ivan |
Lee |
Comparing Ivan
and Peter at first |
130 more |
|
| Before |
5 u + 130 |
5 u |
| Change 1 |
- 1 u - 26 |
+ 1 u + 26 |
| After 1 |
4 u + 104 |
6 u + 26 |
| Change 2 |
+ 3 u + 13 |
- 3 u - 13 |
| After 2 |
7 u + 117 |
3 u + 13 |
20% =
20100 =
1520% x 130
=
20100 x 130
= 26
50% x 26
=
50100 x 26
= 13
50% x 6 u
=
50100 x 6 u
= 3 u
Lee had 334 less cards than Ivan in the end. If another 334 cards are given to Lee, both will have the same number of cards.
7 u + 117 = 3 u + 13 + 334
7 u - 3 u = 13 + 334 - 117
4 u = 230
1 u = 230 ÷ 4 = 23
Number of Lee's cards at first
= 5 u
= 5 x 23
= 115
Answer: 115
