Jeremy had 80 more coins than Cody. Jeremy gave 25% of his coins to Cody. Cody in return gave 80% of his coins to Jeremy. In the end, Jeremy had 186 more coins than Cody. How many coins did Jeremy have at first?
| |
Jeremy |
Cody |
Comparing Jeremy
and Peter at first |
80 more |
|
| Before |
4 u + 80 |
4 u |
| Change 1 |
- 1 u - 20 |
+ 1 u + 20 |
| After 1 |
3 u + 60 |
5 u + 20 |
| Change 2 |
+ 4 u + 16 |
- 4 u - 16 |
| After 2 |
7 u + 76 |
1 u + 4 |
25% =
25100 =
1425% x 80
=
25100 x 80
= 20
80% x 20
=
80100 x 20
= 16
80% x 5 u
=
80100 x 5 u
= 4 u
Jeremy had 186 more coins than Cody in the end. If another 186 coins are given to Cody, both will have the same number of coins.
7 u + 76 = 1 u + 4 + 186
7 u - 1 u = 4 + 186 - 76
3 u = 114
1 u = 114 ÷ 3 = 38
Number of Jeremy's coins at first
= 4 u + 80
= 4 x 38 + 80
= 152 + 80
= 232
Answer: 232
