Dylan had 80 more beads than Henry. Dylan gave 25% of his beads to Henry. Henry in return gave 80% of his beads to Dylan. In the end, Dylan had 141 more beads than Henry. How many beads did Dylan have at first?
| |
Dylan |
Henry |
Comparing Dylan
and Peter at first |
80 more |
|
| Before |
4 u + 80 |
4 u |
| Change 1 |
- 1 u - 20 |
+ 1 u + 20 |
| After 1 |
3 u + 60 |
5 u + 20 |
| Change 2 |
+ 4 u + 16 |
- 4 u - 16 |
| After 2 |
7 u + 76 |
1 u + 4 |
25% =
25100 =
1425% x 80
=
25100 x 80
= 20
80% x 20
=
80100 x 20
= 16
80% x 5 u
=
80100 x 5 u
= 4 u
Dylan had 141 more beads than Henry in the end. If another 141 beads are given to Henry, both will have the same number of beads.
7 u + 76 = 1 u + 4 + 141
7 u - 1 u = 4 + 141 - 76
3 u = 69
1 u = 69 ÷ 3 = 23
Number of Dylan's beads at first
= 4 u + 80
= 4 x 23 + 80
= 92 + 80
= 172
Answer: 172
