Brandon had 170 more coins than Daniel. Brandon gave 20% of his coins to Daniel. Daniel in return gave 50% of his coins to Brandon. In the end, Daniel had 640 less coins than Brandon. How many coins did Brandon have at first?
| |
Brandon |
Daniel |
Comparing Brandon
and Peter at first |
170 more |
|
| Before |
5 u + 170 |
5 u |
| Change 1 |
- 1 u - 34 |
+ 1 u + 34 |
| After 1 |
4 u + 136 |
6 u + 34 |
| Change 2 |
+ 3 u + 17 |
- 3 u - 17 |
| After 2 |
7 u + 153 |
3 u + 17 |
20% =
20100 =
1520% x 170
=
20100 x 170
= 34
50% x 34
=
50100 x 34
= 17
50% x 6 u
=
50100 x 6 u
= 3 u
Daniel had 640 less coins than Brandon in the end. If another 640 coins are given to Daniel, both will have the same number of coins.
7 u + 153 = 3 u + 17 + 640
7 u - 3 u = 17 + 640 - 153
4 u = 504
1 u = 504 ÷ 4 = 36
Number of Daniel's coins at first
= 5 u
= 5 x 36
= 180
Answer: 180
