Jack had 60 more pens than Brandon. Jack gave 20% of his pens to Brandon. Brandon in return gave 50% of his pens to Jack. In the end, Brandon had 117 less pens than Jack. How many pens did Jack have at first?
| |
Jack |
Brandon |
Comparing Jack
and Peter at first |
60 more |
|
| Before |
5 u + 60 |
5 u |
| Change 1 |
- 1 u - 12 |
+ 1 u + 12 |
| After 1 |
4 u + 48 |
6 u + 12 |
| Change 2 |
+ 3 u + 6 |
- 3 u - 6 |
| After 2 |
7 u + 54 |
3 u + 6 |
20% =
20100 =
1520% x 60
=
20100 x 60
= 12
50% x 12
=
50100 x 12
= 6
50% x 6 u
=
50100 x 6 u
= 3 u
Brandon had 117 less pens than Jack in the end. If another 117 pens are given to Brandon, both will have the same number of pens.
7 u + 54 = 3 u + 6 + 117
7 u - 3 u = 6 + 117 - 54
4 u = 69
1 u = 69 ÷ 4 = 23
Number of Brandon's pens at first
= 5 u
= 5 x 23
= 115
Answer: 115
