Fred had 200 more coins than Neave. Fred gave 25% of his coins to Neave. Neave in return gave 60% of his coins to Fred. In the end, Fred had 772 more coins than Neave. How many coins did Fred have at first?
| |
Fred |
Neave |
Comparing Fred
and Peter at first |
200 more |
|
| Before |
4 u + 200 |
4 u |
| Change 1 |
- 1 u - 50 |
+ 1 u + 50 |
| After 1 |
3 u + 150 |
5 u + 50 |
| Change 2 |
+ 3 u + 30 |
- 3 u - 30 |
| After 2 |
6 u + 180 |
2 u + 20 |
25% =
25100 =
1425% x 200
=
25100 x 200
= 50
60% x 50
=
60100 x 50
= 30
60% x 5 u
=
60100 x 5 u
= 3 u
Fred had 772 more coins than Neave in the end. If another 772 coins are given to Neave, both will have the same number of coins.
6 u + 180 = 2 u + 20 + 772
6 u - 2 u = 20 + 772 - 180
18 u = 612
1 u = 612 ÷ 18 = 34
Number of Fred's coins at first
= 4 u + 200
= 4 x 34 + 200
= 136 + 200
= 336
Answer: 336
