Seth had 50 more cards than Peter. Seth gave 20% of his cards to Peter. Peter in return gave 50% of his cards to Seth. In the end, Peter had 88 less cards than Seth. How many cards did Seth have at first?
| |
Seth |
Peter |
Comparing Seth
and Peter at first |
50 more |
|
| Before |
5 u + 50 |
5 u |
| Change 1 |
- 1 u - 10 |
+ 1 u + 10 |
| After 1 |
4 u + 40 |
6 u + 10 |
| Change 2 |
+ 3 u + 5 |
- 3 u - 5 |
| After 2 |
7 u + 45 |
3 u + 5 |
20% =
20100 =
1520% x 50
=
20100 x 50
= 10
50% x 10
=
50100 x 10
= 5
50% x 6 u
=
50100 x 6 u
= 3 u
Peter had 88 less cards than Seth in the end. If another 88 cards are given to Peter, both will have the same number of cards.
7 u + 45 = 3 u + 5 + 88
7 u - 3 u = 5 + 88 - 45
4 u = 48
1 u = 48 ÷ 4 = 24
Number of Peter's cards at first
= 5 u
= 5 x 24
= 120
Answer: 120
